2x-3-x^2-(1/x^2-2)=-7

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Solution for 2x-3-x^2-(1/x^2-2)=-7 equation: 



2x-3-x^2-(1/x^2-2)=-7

We move all terms to the left:

2x-3-x^2-(1/x^2-2)-(-7)=0



Domain of the equation: x^2-2)!=0

x∈R



We add all the numbers together, and all the variables

-1x^2+2x-(1/x^2-2)+4=0

We get rid of parentheses

-1x^2+2x-1/x^2+2+4=0

We multiply all the terms by the denominator


-1x^2*x^2+2x*x^2+2*x^2+4*x^2-1=0

We add all the numbers together, and all the variables

6x^2-1x^2*x^2+2x*x^2-1=0

Wy multiply elements

6x^2-1x^4+2x^3-1=0

We do not support expression: x^4

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